 
          3412
        
        
          Proceedings of the 18
        
        
          th
        
        
          International Conference on Soil Mechanics and Geotechnical Engineering, Paris 2013
        
        
          nominal strain (
        
        
          
        
        
          
        
        
          ), the void ratio (
        
        
          
            e
          
        
        
          ) and the nominal strain rate
        
        
          (
        
        
          T
        
        
          
        
        
          
        
        
          )werecalculated using the displacement.
        
        
          As shown in Fig. 2 a metal pipe was spiralled around the
        
        
          specimenand an isothermal liquid was circulated through this
        
        
          pipe to control the temperature(
        
        
          
            T
          
        
        
          ), which was measured by a
        
        
          thermocouple attached to the upper side of the consolidation
        
        
          cell.To avoid the offset drift of measuring instruments due to
        
        
          changes in the temperature, the whole CRS testing apparatus
        
        
          was preliminarily kept under a testing temperature by
        
        
          circulating isothermal liquid.Then, the measuring instruments
        
        
          were initialized and the CRS test was started.
        
        
          Reconstituted samples were used, to avoid the variability in
        
        
          soil properties for tested samples and to identify only the
        
        
          temperature effect. The samples were made from Louiseville
        
        
          clay, which was obtained from the Louiseville site along the St.
        
        
          Lawrence River in Quebec, Canada. Their main geotechnical
        
        
          properties are as follows: the liquid limit,the plastic limit and
        
        
          the density of soil particles are 71%, 22% and 2.767g/cm
        
        
          3
        
        
          ,
        
        
          respectively. Its detailed properties were referred by Tanaka et
        
        
          al. (2001).
        
        
          Figure1. A typical example of temperature effect on compression curves
        
        
          (after Eriksson, 1989).
        
        
          Figure 2. A schematic view of CRS testing apparatus for controlling
        
        
          temperature.
        
        
          3 TEST RESULTS AND DISCUSSIONS
        
        
          3.1
        
        
          
            Temperature effects on permeability
          
        
        
          Figure 3 shows therelationshipbetween
        
        
          
            e
          
        
        
          -log
        
        
          
            p’
          
        
        
          and
        
        
          
        
        
          
            u
          
        
        
          -log
        
        
          
            p’
          
        
        
          obtained from the CRS tests for Louiseville reconstituted
        
        
          samples. The testing was performed at a constant
        
        
          
            T
          
        
        
          value of 10
        
        
          ℃
        
        
          or 50
        
        
          ℃
        
        
          , while the strain rate was changed during a test. The
        
        
          
            e
          
        
        
          -log
        
        
          
            p’
          
        
        
          curve segments between Points a and b as well as d and
        
        
          f were obtained under the reference strain rate of 3×10
        
        
          -6
        
        
          s
        
        
          -1
        
        
          (
        
        
          T
        
        
          
        
        
          
        
        
          )
        
        
          and that between Points b and d under
        
        
          T
        
        
          
        
        
          
        
        
          /100. In Fig.3,
        
        
          
        
        
          
            u
          
        
        
          generated at 50
        
        
          ℃
        
        
          is clearly smaller than that at 10
        
        
          ℃
        
        
          . It is
        
        
          considered that such a difference in
        
        
          
        
        
          
            u
          
        
        
          is caused by different
        
        
          hydraulic conductivity (
        
        
          
            k
          
        
        
          ). According to JIS A 1227 (2009),
        
        
          
            k
          
        
        
          may be calculated by Eq. (2):
        
        
          T
        
        
          wT n
        
        
          0 t
        
        
          2
        
        
          
            g H H
          
        
        
          
            k
          
        
        
          
            u
          
        
        
          
        
        
          
        
        
          
        
        
          
        
        
          
        
        
          (2)
        
        
          where,
        
        
          
        
        
          w
        
        
          ,
        
        
          
            g
          
        
        
          n
        
        
          ,
        
        
          
            H
          
        
        
          0
        
        
          and
        
        
          
            H
          
        
        
          t
        
        
          are the unit weigh of water, the
        
        
          acceleration of gravity, specimen heights at initial and at each
        
        
          moment (
        
        
          
            t
          
        
        
          ), respectively. The relationships of
        
        
          
            e
          
        
        
          -log
        
        
          
            k
          
        
        
          are shown
        
        
          in Fig. 4, where the
        
        
          
            k
          
        
        
          values were indicated at only normally
        
        
          consolidated (NC) states and they were not calculated in the
        
        
          phase “b-d”, because the strain rate was so small that the value
        
        
          of
        
        
          
        
        
          
            u
          
        
        
          was nearly zero andcould not be measured with sufficient
        
        
          accuracy. When
        
        
          
            k
          
        
        
          at 50
        
        
          ℃
        
        
          and 10
        
        
          ℃
        
        
          is denoted respectively as
        
        
          
            k
          
        
        
          50
        
        
          and
        
        
          
            k
          
        
        
          10
        
        
          ,
        
        
          
            k
          
        
        
          50
        
        
          is larger than
        
        
          
            k
          
        
        
          10
        
        
          and the
        
        
          
            e
          
        
        
          -log
        
        
          
            k
          
        
        
          relationships for
        
        
          
            k
          
        
        
          50
        
        
          and
        
        
          
            k
          
        
        
          10
        
        
          are parallel to each other, as shown in the figure.This
        
        
          means that the ratio of
        
        
          
            k
          
        
        
          50
        
        
          /
        
        
          
            k
          
        
        
          10
        
        
          is constant at the same
        
        
          
            e
          
        
        
          value.
        
        
          It is well known that the viscosity of water is strongly
        
        
          influenced by temperature. Indeed, in the testing method of
        
        
          permeability defined by JIS A 1218 (2009), the measured
        
        
          
            k
          
        
        
          value is calculated at 15
        
        
          ℃
        
        
          (
        
        
          
            k
          
        
        
          15
        
        
          ), taking account of the change in
        
        
          the water viscosity due to temperature. The ratio of
        
        
          
            k
          
        
        
          50
        
        
          /
        
        
          
            k
          
        
        
          10
        
        
          is
        
        
          represented by Eq. (3) with the viscosity coefficient of pure
        
        
          water (
        
        
          
        
        
          T
        
        
          ).
        
        
          50
        
        
          10
        
        
          10
        
        
          50
        
        
          
            k
          
        
        
          
            k
          
        
        
          
        
        
          
        
        
          
        
        
          (3)
        
        
          The ratio
        
        
          
        
        
          
        
        
          10
        
        
          /
        
        
          
        
        
          50
        
        
          is calculated to be 2.39 based on
        
        
          
        
        
          
        
        
          of pure
        
        
          water given in the Chronological Scientific Table (2004). As
        
        
          shown in Fig. 4, the ratio of
        
        
          
            k
          
        
        
          50
        
        
          /
        
        
          
            k
          
        
        
          10
        
        
          for Louiseville clay is 2.44,
        
        
          which is very close to the ratio
        
        
          
        
        
          10
        
        
          /
        
        
          
        
        
          50
        
        
          . Therefore, it may be
        
        
          concluded that the changes in
        
        
          
            k
          
        
        
          and
        
        
          
        
        
          
            u
          
        
        
          with
        
        
          
            T
          
        
        
          are caused by
        
        
          those of the water viscosity.
        
        
          10
        
        
          1
        
        
          10
        
        
          2
        
        
          10
        
        
          3
        
        
          0.8
        
        
          1
        
        
          1.2
        
        
          0
        
        
          100
        
        
          200
        
        
          
            e
          
        
        
          -log
        
        
          
            p’
          
        
        
          (10
        
        
          ℃
        
        
          )
        
        
          
            p'
          
        
        
          
            e
          
        
        
          log (kPa)
        
        
          a
        
        
          b
        
        
          d
        
        
          f
        
        
          
            u
          
        
        
          
        
        
          (kPa)
        
        
          
            e
          
        
        
          -log
        
        
          
            p’
          
        
        
          (50
        
        
          ℃
        
        
          )
        
        
          
        
        
          
            u
          
        
        
          -log
        
        
          
            p’
          
        
        
          (50
        
        
          ℃
        
        
          )
        
        
          
        
        
          
            u
          
        
        
          -log
        
        
          
            p’
          
        
        
          (10
        
        
          ℃
        
        
          )
        
        
          c
        
        
          e
        
        
          phase “a-b” :
        
        
          phase “b-d” :
        
        
          phase “d-f” :
        
        
          /100
        
        
          
        
        
          
        
        
          T
        
        
          0
        
        
          
        
        
          
        
        
          T
        
        
          0
        
        
          
        
        
          e
        
        
          
        
        
          = 3
        
        
          ×
        
        
          10
        
        
          -6
        
        
          s
        
        
          -1
        
        
          
        
        
          T
        
        
          0
        
        
          
        
        
          
        
        
          T
        
        
          0
        
        
          Figure 3. The
        
        
          
            e
          
        
        
          -log
        
        
          
            p’
          
        
        
          relationships obtained from CRS tests.